2j^2+20j+50=0

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Solution for 2j^2+20j+50=0 equation:


Simplifying
2j2 + 20j + 50 = 0

Reorder the terms:
50 + 20j + 2j2 = 0

Solving
50 + 20j + 2j2 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '2'.
2(25 + 10j + j2) = 0

Factor a trinomial.
2((5 + j)(5 + j)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(5 + j)' equal to zero and attempt to solve: Simplifying 5 + j = 0 Solving 5 + j = 0 Move all terms containing j to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + j = 0 + -5 Combine like terms: 5 + -5 = 0 0 + j = 0 + -5 j = 0 + -5 Combine like terms: 0 + -5 = -5 j = -5 Simplifying j = -5

Subproblem 2

Set the factor '(5 + j)' equal to zero and attempt to solve: Simplifying 5 + j = 0 Solving 5 + j = 0 Move all terms containing j to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + j = 0 + -5 Combine like terms: 5 + -5 = 0 0 + j = 0 + -5 j = 0 + -5 Combine like terms: 0 + -5 = -5 j = -5 Simplifying j = -5

Solution

j = {-5, -5}

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